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I've come across something odd whilst doing an exercise for some uni work.
The questions itself is somewhat irrelevant, the problem is this:
The answer to the question is log(3/4)=-0.288...
However, when I enter log(3/4) into my calculator I'm getting -0.125...
Can anyone explain why I may be getting this result rather than the solution to the textbook? (I double checked it with Wolfram Alpha too to make sure they hadn't made an error in the textbook, but Wolfram Alpha agrees with the textbook solution solution)
I'm using a pretty standard mathematical calculator - Casio fx-85GT PLUS. If anyone can offer any reason why it's giving a different result (including "You're being a nonce Yayzeus") I'd be very grateful!
It looks like this
The correct answer is 3.6532... Any insight on what Iβm entering wrong?
Thank you!
Thanks here is the problem.
Thank you to those who helped walk through me the problem!! I guess I was focusing so much on the wrong areas when the answer was literally right in front of me...
Right now all I do is use the root, log or ln button in my calculator and it spits the answer out. Is there a systematical way of calculating this by hand?
Why would logarithms be unpopular after calculators have been invented?
EDIT : Thank you for all the replies guys, these comments and solutions are fantastic!
Forgive me if this is a stupid question.
My little sister claims her chemistry teacher wants them to solve base 10 logarithms without a calculator on a test on Monday. (and she's a little panicked)
Stuff like:
pH = pKa + log ([Base]/[Acid])
pH = 7.6 + log ([0.6]/[0.9])
pH = 7.6 + log (.66)
pH = 7.6 + (-0.18)
pH = 7.42
It's been 10 years since I minor'd in math so I'm ungodly rusty. I've been googling and reading up on logarithms, but I haven't yet found a way to do log(0.66) without a calculator.
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I need help to solve this question without calculator. Thank you!
I am asking this because it might be useful.
I'm looking to get a little more math history, I guess.
How could one find say x in 2^x =33 without the use of a calculator, or a logarithm table, or even a slide rule?
What about the sin(5Ο/12)?
Problems like those, how were they originally solved? Guess and check? but then how were the programs made?
Most of us do not have a calculator that has an [INV] key to inverse a logarithm, so if you need to do an inverse log, you must follow the following to do so (usually when going from a pH to [H^(+)] concentration):
STEP I - Press the [10^(X)] Key
> 10^ (
STEP II - Enter (^(-)1) [to change sign]
> 10^ ((^(-)1)
STEP III - Enter the [pH] and [)]
> 10^ ((^(-)1)[pH])
And then press [ENTER] to solve. Remember that your answer should have as many significant figures as there were decimals with the pH you started with. For example:
Given...
> pH = X.XX
Answer...
> [H^(+)] = Y.XXX*10^(-5) M
Notice how there are 3 X's (Sig Figs) in the given, and there are 3 X's in the decimal places of the answer.
Is this possible? For instance, if we had y = log3X (3 being the base, I'm not sure how to make it small,) I'd be able to graph it by putting logx/log3 in Y1 in the calculator. However, if we had y=log3(x+9) + 2 , I can't figure out how to graph that. Thanks!
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